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Old 11-07-2007, 06:20 PM   #31
BumbleBeeMouth
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Quote:
Originally Posted by bardy
uh no that is the solution

there are a few ways to get to it but that is the right answer
I dont think you understand what i was asking. of course its the solution, but i was asking if it was a solution based on a technicality that wouldnt occur in practice.

 
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Old 11-07-2007, 06:21 PM   #32
BumbleBeeMouth
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Or perhaps you do understand and i havent noticed.

 
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Old 11-07-2007, 06:21 PM   #33
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I just dont know anything anymore...

 
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Old 11-07-2007, 08:02 PM   #34
Crunchy Black
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i solved it during analytical chemistry

 
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Old 11-07-2007, 08:07 PM   #35
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Quote:
Originally Posted by BumbleBeeMouth
1. a = b + 1 1. Given
2. (a-b)a = (a-b)(b***) 2. Multiplication Prop. of =
3. a2 - ab = ab + a - b2 - b 3. Distributive Propoerty
4. a2 - ab -a = ab + a -a - b2 - b 4. Subtraction Prop. of =
5. a(a - b - 1) = b(a - b - 1) 5. Distributive Propoerty
6. a = b 6. Division Property of =
7. b + 1 = b 7. Transitive Property of = (Steps 1, 7)
8. Therefore, 1 = 0 8. Subtraction Prop. of =
this would be one of those idiot traps that do their best to divide by zero without your noticing it around step 6.


my problem was a real problem so naturally noone on netphoria who would purport to having ever taken a math course came anywhere near the thread

Last edited by Crunchy Black : 11-07-2007 at 09:31 PM.

 
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Old 11-08-2007, 01:18 AM   #36
yo soy el mejor
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*pats crunchy black on the back*

 
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